(x+20)(x+3)=x^2-10

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Solution for (x+20)(x+3)=x^2-10 equation: 



(x+20)(x+3)=x^2-10

We move all terms to the left:

(x+20)(x+3)-(x^2-10)=0

We get rid of parentheses

-x^2+(x+20)(x+3)+10=0

We multiply parentheses ..

-x^2+(+x^2+3x+20x+60)+10=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+3x+20x+60)+10=0

We get rid of parentheses

-1x^2+x^2+3x+20x+60+10=0

We add all the numbers together, and all the variables

23x+70=0

We move all terms containing x to the left, all other terms to the right

23x=-70

x=-70/23

x=-3+1/23

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